Answer:
Explanation:
The rotation rate of the man is:
The resultant rotation rate of the system is computed from the Principle of Angular Momentum Conservation:
![(90\,kg)\cdot (5\,m)^{2}\cdot (0.16\,\frac{rad}{s} ) = [(90\,kg)\cdot (5\,m)^{2}+20000\,kg\cdot m^{2}]\cdot \omega](https://tex.z-dn.net/?f=%2890%5C%2Ckg%29%5Ccdot%20%285%5C%2Cm%29%5E%7B2%7D%5Ccdot%20%280.16%5C%2C%5Cfrac%7Brad%7D%7Bs%7D%20%29%20%3D%20%5B%2890%5C%2Ckg%29%5Ccdot%20%285%5C%2Cm%29%5E%7B2%7D%2B20000%5C%2Ckg%5Ccdot%20m%5E%7B2%7D%5D%5Ccdot%20%5Comega)
The final angular speed is:
<span>So
the mural has an area of 18m squared
=> A = 18m^2
in getting the area of a square we use to formula = s^2, but since the area is
already given, we need to find the value
of each sides of the square. Thus, we simply need to do it backward.
we need to find the square root of the area
=> square root of 18m^2
=> 4.24m
Therefore that mural has a sides of approximately 4.24 meters</span>
What are the following statements? If there's one that mention a description of current action, or motion, that's your answer.
The answer is d hope this helps
Assuming that it continues to accelerate at the same rate it will take another 10 seconds to reach 40 m/s.
Answer:
Explanation:
Since the first question states that there is a change in the velocity from rest to 20 m/s in 10 seconds time interval. So the acceleration experienced by the car during this 10 seconds should be determined first as follows:
Acceleration = (final velocity-initial velocity)/Time
Acceleration = (20-0)/10 = 2 m/s².
So this means the car is traveling with an acceleration of 2 m/s².
As it is stated that the car continues to move with same acceleration, then in the second case, the acceleration is fixed as 2 m/s², initial velocity as 20 m/s and final velocity as 40 m/s. So the time taken for the car to reach this velocity with the constant acceleration value will be as follows:
Time = Change in velocity/Acceleration
Time = (40-20)/2 = 20/2=10 s
So again in another 10 seconds by the car to reach 40 m/s from 20 m/s. Similarly the car will take a total of 20 seconds to reach from rest to 40 m/s value for velocity.
