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seropon [69]
1 year ago
8

Alyse runs to her classroom which is 20 meters away. She forgets her physics book in her locker and must return 20 meters in the

direction from whence she came. If her total trip takes 3 minutes, what is Alyse’s average velocity? NEED HELPP ASAPPPP!!!!!
Physics
1 answer:
notka56 [123]1 year ago
3 0

The average velocity of Alyse is 0 m/s.

<h3>What is the average velocity of an object or a person?</h3>

The average velocity of a person is the average of all the velocities of moving as it moves.

Velocity on its own is the ratio of the displacement of a body and the time taken for that displacement.

Mathematically:

  • Average velocity = total displacement / time taken

Displacement is a vector quantity that measures the distance traveled by a moving body in a specific direction.

Hence, average velocity and velocity are both vector quantities.

Displacement takes a measure of the shortest possible distance along a straight line from the beginning of the motion until the end of the motion.

Calculating the average velocity of Alyse:

Assuming the initial direction is positive and n=backeard direction is negative:

Total displacement = 20 m + - (20 m)

Total displacement = 0 m

total time = 3 minutes

Average velocity = 0 m/ 3

Average velocity = 0 m/s

Learn more about average velocity at: brainly.com/question/4931057

#SPJ1

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Answer:

Part a)

Mass of m2 is given as

m_2 = \frac{20}{3} kg

Part b)

Angular acceleration is given as

\alpha = 1.96 rad/s^2

Part c)

Tension in the rope is given as

T = 176.6 N

Explanation:

Part a)

When m1 and m2 both connected to the cylinder then the system is at rest

so we can use torque balance here

m_1g r_1 = m_2 g r_2

20 g(0.5) = m_2 g(1.5)

10 = 1.5 m_2

m_2 = \frac{20}{3} kg

Part b)

When block m_2 is removed then system becomes unstable

so force equation of mass m1

m_1g - T = m_1 a

also we have

T r_1 = I\alpha

now we have

m_1g = \frac{I a}{r_1^2} + m_1 a

a = \frac{m_1g}{\frac{I}{r_1^2} + m_1}

a = \frac{20 (9.81)}{\frac{45}{0.5^2} + 20}

a = 0.981 m/s^2

so angular acceleration is given as

\alpha = \frac{a}{r_1}

\alpha = \frac{0.981}{0.5}

\alpha = 1.96 rad/s^2

Part c)

Tension in the rope is given as

T = \frac{I\alpha}{r_1}

T = \frac{45 (1.96)}{0.5}

T = 176.6 N

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4 years ago
Help asap!
patriot [66]

Answer:

220 V

Explanation:

r_{1} = 20 ohm\\r_{2} = 30ohm\\r_{3} = 60ohm

As the resistors are connected in series,

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= 20 + 30 + 60

= 110 ohms

V = IR

= 2 * 110

= 220 V

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