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kompoz [17]
4 years ago
13

Compare and contrast a series and parallel circuit. Give at least one way that they are alike and one way that they are differen

t
Physics
2 answers:
masya89 [10]4 years ago
6 0
A parallel circuit has multiple paths from the energy source to the resistors (e.x., lightbulbs). If one bulb was to burn out, the rest would stay on, unlike a series circuit. If one bulb was to burn out, the circuit is no longer fully connected because there is only one path from the energy source to the resistors. But, despite these differences, they are similar in the way that they do have paths from the energy source to the resistors.
Alinara [238K]4 years ago
4 0

Explanation:

A system of resistors can be arranged in two ways i.e. series combination and parallel combination.

In series combination of resistors, the current flowing across each and every resistor is same while the potential difference divides. The equivalent resistance in series combination is given by :

R_{eq}=R_1+R_2+.......+R_n

In parallel combination of resistors, the potential difference across each and every resistor is same while the current divides. The equivalent resistance is parallel combination is given by :

\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+.........+\dfrac{1}{R_n}  

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Point charges q1 = 14 µC and q2 = −60 µC are fixed at r1 = (5.0î − 4.0ĵ) m and r2 = (9.0î + 7.5ĵ) m. What is the force (in N) of
Lostsunrise [7]

Answer:

The force on q₁ due to q₂ is (0.00973i + 0.02798j) N

Explanation:

F₂₁ = \frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|}

Where;

F₂₁ is the vector force on q₁ due to q₂

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r₂₁ is the unit vector

|r₂₁| is the magnitude of the unit vector

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r₂₁ = [(9-5)i +(7.4-(-4))j] = (4i + 11.5j)

|r₂₁| = \sqrt{(4^2)+(11.5^2)} = \sqrt{148.25}

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F_2_1=\frac{K|q_1|q_2|}{r^2}.\frac{r_2_1}{|r_2_1|} = \frac{8.99X10^9(14X10^{-6})(60X10^{-6})}{148.25}.\frac{(4i + 11.5j)}{\sqrt{148.25} }

      = 0.050938(0.19107i + 0.54933j) N

      = (0.00973i + 0.02798j) N

Therefore, the force on q₁ due to q₂ is (0.00973i + 0.02798j) N

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