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Hoochie [10]
3 years ago
10

What is the difference? 14x over 17 minus 3x over 17 (14x/17 - 3x/17)

Mathematics
1 answer:
Gre4nikov [31]3 years ago
7 0
14x-3x= 11x and the 17 stays the same, so the answer is 11x/17 or answer B.

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Find all the zeros of 2x4+x3-14x2-19x-6 two of its zeros are -2 and -1
GalinKa [24]

Answer:

-2,\ -1,\ -\dfrac{1}{2},\ 3.

Step-by-step explanation:

Consider polynomial 2x^4+x^3-14x^2-19x-6.

If x=-2 is its zero, then you can divide the polynomial 2x^4+x^3-14x^2-19x-6 by x+2 and get

2x^4+x^3-14x^2-19x-6=(x+2)(2x^3-3x^2-8x-3).

If x=-1, then the polynomial 2x^4+x^3-14x^2-19x-6 can be rewritten as

2x^4+x^3-14x^2-19x-6=(x+2)(x+1)(2x^2-5x-3).

The quadratic polynomial has roots

x_{1,2}=\dfrac{-(-5)\pm\sqrt{(-5)^2-4\cdot2\cdot(-3)}}{2\cdot 2}=\dfrac{5\pm \sqrt{25+24}}{4}=\dfrac{5\pm \sqrt{49}}{4}=3,-\dfrac{1}{2}.

Then the polynomial 2x^4+x^3-14x^2-19x-6 has zeros -2,\ -1,\ -\dfrac{1}{2},\ 3.



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