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3 years ago

A rectangle on a coordinate plane has vertices at (7,5),(-7,5),(-7,-2),and (7,-2) what is the perimeter of the rectangle?

Mathematics

1 answer:

Nadya [2.5K]3 years ago

5 0

Answer:

Your Perimiter is 42

Step-by-step explanation:

Distance from 7,5 to -7,5 is 14

Distance from -7,5 to -7,-2 is 7

Then we double both those numbers as it is a rectangle

2l + 2w = Per...

28 + 14 = 42

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At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37

monitta

Answer:

Half-life of the goo is 49.5 minutes

$G(t)= 300e^{-0.014t}$

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let $M_0\,,\,M_f$ denotes initial and final mass.

$M_0=300\,\,grams\,,\,M_f=37.5\,\,grams$

According to exponential decay,

$\ln \left ( \frac{M_f}{M_0} \right )=-kt$

Here, t denotes time and k denotes decay constant.

$\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014$

So, half-life of the goo in minutes is calculated as follows:

$\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes$

Half-life of the goo is 49.5 minutes

$\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}$

So,

$G(t)= M_f=M_0e^{-kt}$

Put $M_0=300\,\,grams\,,\,k=0.014$

$G(t)= 300e^{-0.014t}$

Put t = 32 minutes

$G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams$

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3 years ago

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Answer:

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21*25=525

24*18=432

525-432=93

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2 years ago

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Answer:

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9x + 31y is the most simplified version of your expression! I believe your question is missing some information but I would love to help in any way I can. Here is how I simplified +9x + 5y + 26y into its simplest form.

Step 1: Add like terms (Add the numbers together with the same terms)

9x + ( 5y + 26y)

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