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Marta_Voda [28]

3 years ago

15

Mrs. Smith surveyed her class of 20 students to find out what sports they played. The results are recorded below. Based on the t

able’s rates, how many students out of 40 would play baseball?

2 answers:

Anika [276]3 years ago

6 0

Answer:

where is the chart?

Step-by-step explanation:

Irina-Kira [14]3 years ago

5 0

Answer:

20

Step-by-step explanation:

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For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

Suppose the same quantity is measured but with a more precise method giving an average and standard deviation of 15.0 ± 2.5. how

abruzzese [7]

To solve this, we use the z test.

The formula:

z = (x – u) / s

where x is sample value = 20, u is the mean = 15, and s is the standard deviation = 2.5

z = (20 – 15) / 2.5

z = 2

Since we are looking for values greater than 20, this is right tailed test. We use the standard distribution tables to find for P.

P = 0.0228

Therefore:

number of students = 100 * 0.0228 = 2.28

<span>2 to 3 students will get greater than 20 measurement</span>

7 0

3 years ago

If Anthony wants to end his day at Navy Pier (10,9) will it be more efficient to go to the Chicago theater (0,3) and then Millen

HACTEHA [7]

Distance formula
D = √((x1 - x2)2 + (y1 - y2)2) We have three distances that we are dealing with. Between the Theater and the Park, between the Theater and the Pier, and between the Park and the pier. In both routes we have to go between the Theater and the Park. The distance between those is the same regardless of which way we go, so we can ignore doing the math for that. That leaves us two distances. Let's plug them in. Theater to PierD = √((0 - 10)2 + (3 - 9)2) = √(100 + 36) ≈ 11.6619 Park to PierD = √((2 - 10)2 + (1 - 9)2) = √(64 + 64) ≈ 11.3137 11.3 < 11.7

7 0

3 years ago

What is the value of x enter your answer in the Box

Dimas [21]

61.4 is the value of x

7 0

3 years ago

an official playing field (including end zone) for the indoor football league has a length 39 yd longer than its width. the peri

ch4aika [34]

Answer:

42

Step-by-step explanation:

39+39 = 78

162 - 78 = 2 lengths =84

84/2 = 42

5 0

3 years ago