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3 years ago

I wanna know the lateral surface area and the total surface answer

Mathematics

1 answer:

Darina [25.2K]3 years ago

8 0

Lateral Surface Area = 4s^2
LSA = 4*4^2
LSA = 64 cm^2

Total Surface Area = 6s^2
TSA = 6*4^2
TSA = 96 cm^2

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(-1, -5) (-2, -4) (-5,-1) (-4, -2)

notka56 [123]

Answer:

(-4, -2)

Step-by-step explanation:

A = (-1, 2)

Add (-3, -4) to that and you get ...

A' = (-1-3, 2-4) = (-4, -2) . . . . matches the last choice

The translation function has the effect of moving the point left 3 and down 4. You can count grid squares on the graph to see that A' ends up at (-4, -2).

8 0

4 years ago

If the first number is increased by 7 and the second number is reduced by 6 times, the sum of these numbers is 29.

Marta_Voda [28]

Answer:

First number = 20

Second number = 12

Explanation:

Let the 1st number be x

Let the 2nd number be y

=====================

Condition 1

$\sf \rightarrow x + 7 + \dfrac{y}{6} = 29$

$\rightarrow \sf x=-\dfrac{y}{6}+22$

=====================

Condition 2

$\rightarrow \sf 2y - (x - 5) = 9$

$\rightarrow \sf x = 2y -4$

=====================

Substitute equations

$\rightarrow \sf -\dfrac{y}{6}+22 = 2y-4$

$\rightarrow \sf y=12$

=====================

Find value of 1st number

$\rightarrow \sf x = 2y - 4$

$\sf \rightarrow x = 2(12) - 4$

$\rightarrow \sf x = 20$

7 0

2 years ago

Which of the following represents the factorization of trinomal below

My name is Ann [436]

A is the correct answer.......

Here is the work shown:

x^2-x-20

A is the correct answer because when using the distributive property it is the only example that results in x^2-x-20.

(x+4)(x-5)

x*x=x^2, x*-5=-5x, 4*x=4x, 4*-5=-20. Now combine all alike terms for your final answer. x^2-x-20..

please vote my answer brainliest. thanks!

5 0

3 years ago

What is the area of this trapezoid?

pantera1 [17]

Answer:

Area=80 units squared

A=base*height

A=base*height/2

Step-by-step explanation:

7*8=56/2=28

3*8=24

28+28+24

56+24

5 0

4 years ago

Read 2 more answers

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that perpendicular lines have negative reciprocal slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$

4 0

3 years ago