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noname [10]
2 years ago
8

Explain the errors and write the correct answers. Gary converts kilograms to grams as shown: 4.25 kg = 4.25 x 100 = 425 grams

Mathematics
1 answer:
Andrej [43]2 years ago
3 0

Answer:

Gary needed to multiply by 1000 instead of 100.

Step-by-step explanation:

The conversion from kilograms to grams is to multiply by 1000.

#teamtrees #WAP (Water And Plant)

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Solve x/3 = x+2/2. X=
Leni [432]

Answer:

I will assume that the term "x+2/2" is meant to be "(x + 2)/2)."  Otherwise the equation would read (x/3) = x + 1

Step-by-step explanation:

(x/3) = (x + 2)/2

x = 3*(x+2)/2   [Multiply both sides by 3]

x = (3x + 6)/2

x = (3/2)x + 6/2

x - (3/2)x = 3

-0.5x = 3

x = -6

====================

Check:

Does (x/3) = (x + 2)/2 for x = -6?

(-6/3) = (-6 + 2)/2

-2 = -4/2

-2 = -2  YES

6 0
2 years ago
A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and
Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95  

= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95  

=P( z \leq \displaystyle\frac{x - 5}{1})=0.05  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4  

Hence,  4 trays should he prepared, if the owner wants a service level of at least 95%.

3 0
3 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
2 years ago
You and your friends want to rent a limo on prom night.
ikadub [295]
Hey there!

You would be able to rent the limo for 4 hours plus the booking fee.

75 x 4 = 300

300 + 50 = 350

350 = 350

Hope this helps you! :)

Hugs!
- Nicole
4 0
3 years ago
Read 2 more answers
Multiple choice/ please help!!!
Oxana [17]

Answer:

All are right answer

But one is not (C)

There will no cot

4 0
2 years ago
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