Answer:
-3.82ºC is the freezing point of solution
Explanation:
We work with the Freezing point depression to solve the problem
ΔT = m . Kf . i
ΔT = Freezing point of pure solvent - freezing point of solution
Let's find out m, molality (moles of solute in 1kg of solvent)
15 g / 58.45 g/mol = 0.257 moles of NaCl
NaCl(s) → Na⁺ (aq) + Cl⁻(aq)
i = 2 (Van't Hoff factor, numbers of ions dissolved)
m = mol /kg → 0.257 mol / 0.250kg = 1.03 m
Kf = Cryoscopic constant → 1.86 ºC/m (pure, for water)
0ºC - Tºf = 1.03m . 1.86ºC/m . 2
Tºf = -3.82ºC
Wouldn’t it be pollution? Or......
Im pretty sure its Taxes?
Answer:
1.67 M
Explanation:
75.0 g *1 mol/180 g = (75/180) mol of glucose
250 mL = 0.250 L
(75/180)/0.250 = 1.67 mol/L =1.67 M
The status of the state of matter of a material defines the phase. Pellet currently case 16 is defined; three of which solid, liquid and gas are referred to as conventional cases. There are a total of 16 state currently defined, these classic except; liquid crystal, amorphous solid, magnetic regularly, superconducting, superfluid, the Bose-Einstein condensation, Rydberg molecules, plasma (ionized gas), the quark-gluon plasma, degenerate matter, Superkate, the stringy liquid and SuperCam mine. Daily life in general, solid materials, include liquid or gaseous, but outside world, 99% of the material in the universe plasma (ionized gas) is in the form.
