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Tju [1.3M]
3 years ago
5

1 point

Chemistry
1 answer:
Dafna11 [192]3 years ago
7 0

Answer:ee

Explanation:

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An isotope of cesium has 55 protons and 78 neutrons. What is the mass number of this isotope?
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The concentration of hydronium ions is greater than 1 × 10–7 for basic solutions. True False
Nataly [62]

Answer : The given statement is, false.

Explanation :

Ionic product of water : It is defined as the product of the concentration of hydrogen ion and the concentration of hydroxide ion.

The mathematical expression will be,

[H^+][OH^-]=10^{-14}

When the concentration of hydrogen ion and hydroxide ion are equal then the solution is neutral and the value will be, 1\times 10^{-7}. And the pH of the solution is, 7.

When the concentration of hydrogen ion is greater than 1\times 10^{-7} then the solution is acidic in nature. And the pH of the solution is, less than 7.

When the concentration of hydrogen ion is less than 1\times 10^{-7} then the solution is basic in nature. And the pH of the solution is, greater than 7.

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5 0
3 years ago
2) Calculate the percent composition of each element in Mgso,
iogann1982 [59]

Answer:

2)

\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%

3)

\% Ag=93.1\%\\\\\% O=6.9\%

Explanation:

Hello!

2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:

\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%

3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:

\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%

Best regards!

7 0
3 years ago
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