Answer:
Step-by-step explanation:
p=sec0+tan0
=1/cos0 + sin0/cos0
=(1+sin0)/cos0
square both sides
(1+sin)^2 /cos^2 = p^2
(1+sin)^2/(1 - sin^2 ) = p^2
(1+sin)^2/((1-sin)(1+sin)) = p^2
(1+sin)/(1-sin)=p^2
1+sin=p^2-p^sin
sin+p^2sin=p^2-1
sin(1+p^2)=(p^2-1)
sin=(1-p^2)/(1+p^2)
cosec=1/sin
=(1+p^2)/(1-p^2)
Determine whether the relation is a function.<br><br>
(-3,3), (-2,2), (-1,1), (1,-1), (2,-2), (3,-3)
Luba_88 [7]
Answer:
Function
Step-by-step explanation:
Because there is an output for every input listed of its opposite.
Answer:
Step-by-step explanation:
it is b
You get the answer x+5/x+3.
This is because all of the fractions have the same denominator, so just add the numerators and put them over x+3.
<span>B. 1 + 1 = 2
C. 2 + 0 = 2</span>
