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3 years ago

Sharee and her two sisters ate 3 5 of a pizza. How much of the pizza did each girl have? A) 1 3 B) 1 5 C) 2 15 D) 3 10

1 answer:

7 0

Sharee and her two sisters ate 3 /5 of a pizza. How much of the pizza did each girl have? A) 1 /3 B) 1/ 5 C) 2 /15 D) 3 /10

Answer:

B) 1/ 5

Step-by-step explanation:

Number of persons = Sharee and her two sisters = 3 persons

Quantity of pizza eaten = 3/5

Each person ate:

3 persons = 3/5 pizza

1 person = x pizza

Cross Multiply

3 × x = 3/5 × 1

x = 3/5 × 1/3

x = 3/5 ÷ 3

x = 3/5 × 1/3

x = 1/5

Hence, each person ate 1/5 pizza.

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What is3\8 +5/2 need help

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3/8 + 5/2
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3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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3 years ago

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Dmitriy789 [7]

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Answer:

E) 300

F) 510

Step-by-step explanation:

E) 6*50=300

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4 years ago

You buy a commemorative coin for $110. Each year, t, the value V of the coin increases by 4%

faltersainse [42]

A. f(x)= 100*1.04^t
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