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3 years ago

Solve for b. Round your answer to the nearest whole degree.

Mathematics

1 answer:

Talja [164]3 years ago

8 0

Answer:

44°

Step-by-step explanation:

From sin rule:

a / sin A = b / sin B = c / Sin C

3.6 / sin b = 5.1 / sin 100

Cross multiply :

5.1 * sinb = 3.6 * sin 100

Sin b = 3.5453079 / 5.1

Sin b = 0.6951584

b = sin^-1(0.6951584)

b = 44.039

b = 44°

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$\bf x(t)=0.5t^2+0.4t-87.30\implies x(t)=\cfrac{1}{2}t^2+\cfrac{2}{5}t-\cfrac{873}{10}
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x=\cfrac{1}{2}\left( t^2+\cfrac{4}{5}t+\boxed{?}^2 \right)-\cfrac{873}{10}$

so, as you already know, we'll borrow from our good friend Mr Zero, 0, to get that missing value for the perfect square trinomial,

$\bf x=\cfrac{1}{2}\left[ t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2-\left( \cfrac{2}{5} \right)^2 \right]-\cfrac{873}{10}
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x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\cfrac{4}{25}-\cfrac{4}{25} \right]-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2\right]-\cfrac{2}{25}-\cfrac{873}{10}
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$\bf x=\cfrac{1}{2}\left( t+\frac{2}{5} \right)^2-\cfrac{4369}{50}\implies x+\cfrac{4369}{50}=\cfrac{1}{2}\left( t+\frac{2}{5} \right)^2
\\\\\\
2x+\cfrac{4369}{25}=\left( t+\frac{2}{5} \right)^2\implies \sqrt{2x+\cfrac{4369}{25}}=t+\cfrac{2}{5}
\\\\\\
\sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5}=t$

$\bf -------------------------------\\\\
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\\\\\\
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