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Alja [10]
3 years ago
7

5 STARS!!!

Mathematics
2 answers:
Arlecino [84]3 years ago
6 0

Answer:

The following are not permitted:  g = 0, g + -4 and g= 3

Step-by-step explanation:

Recall that division by zero is not defined or allowed.  Thus, we take the denominator, g^3+g^2−12g and set it equal to zero, to identify the x values at which the den. is zero:

g^3+g^2−12g = 0

g(g^2 + g - 12) = 0

g(g+4)(g-3) = 0 => g = 0, g + -4 and g= 3.

These three x values constitute the domain restrictions; they are not permitted.

Vikki [24]3 years ago
6 0

Answer:

g = -4, 3, 0

Step-by-step explanation:

(g² + 2g - 8)/(g³ + g² - 12g)

(g - 2)(g + 4)/g(g² + g - 12)

(g - 2)(g + 4)/g(g + 4)(g - 3)

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