Answer:
125.4
Step-by-step explanation:
Given
Required
Round to 1 decimal place
Up till the first decimal place, the number is:
The digit after .3 is 5
The conditions for approximation are:
- If n > 4, approximate to 1
In this case: 5 > 4, so we approximate to 1
Add this "1" to the last digit of 125.3. This becomes 125.4
<em>Hence: when the number is approximated to 1 decimal place, the digit is 125.4</em>
Answer:
Determine the type of elasticity of demand
<h3>
Answer: Choice B) 
</h3>
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Work Shown:
y = (3/2)x + 4
2y = 3x + 8 .... multiply both sides by 2
0 = 3x + 8 - 2y
3x-2y+8 = 0
The original equation transforms to 3x-2y+8 = 0. It is in the form Ax+By+C = 0. We see that A = 3, B = -2, C = 8. This form is very useful to help find the distance from a point to this line.
The formula we will use is
where A,B,C were the values mentioned earlier. The p,q are the x and y coordinates of the point given. So p = 9 and q = -2
Plugging all that in gives...
Answer:
A volcano ejected with an initial velocity of 304 feet per second.
The height in feet is given by the equation H=-16t^2+ 304t where t is the time in seconds.
We will use the equation that traces the path of the projectile to determine the following information:
1) The time it takes the projectile to reach its maximum height (using the vertex formula: t=-b/2a)
The equation; H = -16t^2 + 304t, a=-16; b=304
t = -304/2°(-16)
t = 9.5 sec to reach max height
2) The maximum height of the projectile (use the result from part 1 to find the maximum height of the projectile)
t = 9.5
H = -16(9.5^2) + 304(9.5)
h = = -1444 + 2888
h = 1444 ft is the max height
3) Find the time it takes the projectile to return to the ground. Assume that the projectile starts at height H=0.
-16t^2 + 304t = 0
factor out -16t
-16t(t - 19) = 0
t = 19 sec to reach the ground
Step-by-step explanation:
