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Anton [14]
3 years ago
10

If f(x)=25-x^2 and g(x)=x+5, what is (f/g)(x)? Write your answer in the simplest form.

Mathematics
2 answers:
Flura [38]3 years ago
4 0
F(x) = -x² + 25
g(x) = x + 5

(f ÷ g)(x) = ⁻ˣ²⁺²⁵/ₓ₊₅
(f ÷ g)(x) = ⁻¹⁽ˣ⁺⁵⁾⁽ˣ⁻⁵⁾/ₓ₊₅
(f ÷ g)(x) = -x + 5
siniylev [52]3 years ago
4 0
F(x) = 25-x^2 
g(x) =x+5

(25-x^2)/(x+5)
Factor the 25-x^2
(-x+5)(x+5)/(x+5)
The (x+5)s are common therefore cross out leaving you with <span>(f/g)(x)= -x+5</span>
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Use the rational zeroes theorem to state all the possible zeroes of the following polynomial:
Mkey [24]

Answer:

All the possible zeroes of the polynomial: f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4 are  ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3} by using rational zeroes theorem.

Step-by-step explanation:

Rational zeroes theorem gives the possible roots of polynomial f(x) by taking ratio of p and q where p is a factor of constant term and q is a factor of the leading coefficient.

The polynomial f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4

Find all factors (p) of the constant term.

Here we are looking for the factors of 4, which are:

±1 , ±2 and ±4

Now find all factors (q) of the coefficient of the leading term

we are looking for the factors of 3, which are:

±1 and ±3

List all possible combinations of ± \frac{p}{q}  as the possible zeros of the polynomial.

Thus, we have ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3} as the possible zeros of the polynomial

Simplify the list to remove and repeated elements.

All the possible zeroes of the polynomial: f(x) = 3x^{6} + 4x^{3} - 2x^{2} +4 are  ±1 , ±2 ,  ±4 ,  ±\frac{1}{3} , ±\frac{2}{3}  , ±\frac{4}{3}

Learn more about Rational zeroes theorem here -https://brainly.ph/question/24649641

#SPJ10

7 0
2 years ago
Does anyone know this or how to do it?
Pavlova-9 [17]
Copy and paste into search bar and it shoudl come up
7 0
3 years ago
Please I need help. Answer with examples I am so confuzzled!
Marianna [84]
Sorry not sure about this
4 0
3 years ago
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