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3 years ago

What is the explicit formula for this geometric sequence?8,4,2,1

Mathematics

1 answer:

bazaltina [42]3 years ago

6 0

the n th term formula ( explicit formula ) for a geometric sequence is

$a_{n}$ = $a_{1}$ $(r)^{n-1}$

where r is the common ratio and $a_{1}$ the first term

here $a_{1}$ = 8 and r = $\frac{4}{8}$ = $\frac{2}{4}$ = $\frac{1}{2}$

$a_{n}$ = 8( $\frac{1}{2}$ )^n - 1 → C

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Norma-Jean [14]

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3 years ago

I don't understand this equation

aliya0001 [1]

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3 years ago

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

Leviafan [203]

Answer:

Probability of having student's score between 505 and 515 is 0.36

Given that z-scores are rounded to two decimals using Standard Normal Distribution Table

Step-by-step explanation:

As we know from normal distribution: z(x) = (x - Mu)/SD

where x = targeted value; Mu = Mean of Normal Distribution; SD = Standard Deviation of Normal Distribution

Therefore using given data: Mu (Mean) = 510, SD = 10.4 we have z(x) by using z(x) = (x - Mu)/SD as under:

In our case, we have x = 505 & 515

Approach 1 using Standard Normal Distribution Table:

z for x=505: z(505) = (505-510)/10.4 gives us z(505) = -0.48

z for x=515: z(515) = (515-510)/10.4 gives us z(515) = 0.48

Afterwards using Normal Distribution Tables and rounding the values to two decimals we find the probabilities as under:

P(505) using z(505) = 0.32

Similarly we have:

P(515) using z(515) = 0.68

Now we may find the probability of student's score between 505 and 515 using:

P(505 < x < 515) = P(515)-P(505) = 0.68 - 0.32 = 0.36

PS: The standard normal distribution table is being attached for reference.

Approach 2 using Excel or Google Sheets:

P(x) = norm.dist(x,Mean,SD,Commutative)

P(505) = norm.dist(505,510,10.4,1)

P(515) = norm.dist(515,510,10.4,1)

Probability of student's score between 505 and 515= P(515) - P(505) = 0.36

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3 years ago

3 cousins are named Jasmine and Kyra and Louisa.

vodka [1.7K]

Jasmine is 12 and kyra is 30

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3 years ago

If a contractor receives payment of 1,480.00, pays 1,111.74 for labor and materials and then deducts 18% of the payment for over

crimeas [40]

In the given question, the contractor receives a payment of 1480.00. Then he has to pay for labours and materials and this amounts to 1111.74. On the remaining amount the contractor has to deduct 18% as overhead cost.
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Now the overhead cost of 18% needs to be found from the amount of money left.
Then the overhead cost = 368.26 * 18/100
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So the labour ost takes away 1111.74 and the overhead cost takes out 66.28 from the total payment of 1480.
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4 years ago