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Tanya [424]
2 years ago
15

Find p(1) if the polynomial is p (X)=x2-3x+6​

Mathematics
1 answer:
sveticcg [70]2 years ago
8 0

Step-by-step explanation:

hope it helps you..........

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Given that y is directly proportional to x. If y = 30 and x= 5, write an equation that connects y with x.
Licemer1 [7]

Given:

y is directly proportional to x.

y=30 when x=5

To find:

The equation that connects y with x.

Solution:

It is given that, y is directly proportional to x. So,

y\propto x

y=kx                     ...(i)

Where, k is the constant of proportionality.

We have, y=30 when x=5. Substituting these values in (i), we get

30=k(5)

Divide both sides by 5.

\dfrac{30}{5}=k

6=k

Substituting k=6 in (i), we get

y=6x  

Therefore, the required equation is y=6x.

8 0
2 years ago
There are 32 students in Jenna's class. Jenna brought in 14 cupcakes. Which equation can be used to find the number of cupcakes
snow_lady [41]

Answer:

n = 32 - 14  (= 18)

Step-by-step explanation:

You haven't given the answer options, however I assume it will be written in this form. I.e. the number of cupcakes still needed is just the total number of students (32) minus the number that Jenna bought (14).

so n = 32 -14 (=18)

3 0
3 years ago
HELP I NEED HELP ASAP
Bezzdna [24]

Answer:

sorry I did not learn those yet

6 0
3 years ago
Find f(3) if f(x) = -2x + 14.<br><br><br> PLS HELP
Pachacha [2.7K]

Answer:

8

Step-by-step explanation:

Substitute 3 for x

-2x + 14

-2(3) + 14

-6 + 14 = 8

4 0
2 years ago
Read 2 more answers
what is the smallest positive integer a such that the intermediate value theorem guarantees a zero exists between 0 and a?
liberstina [14]

The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

What is the intermediate value theorem?

Intermediate value theorem is theorem about all possible y-value in between two known y-value.

x-intercepts

-x^2 + x + 2 = 0

x^2 - x - 2 = 0

(x + 1)(x - 2) = 0

x = -1, x = 2

y intercepts

f(0) = -x^2 + x + 2

f(0) = -0^2 + 0 + 2

f(0) = 2

(Graph attached)

From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3

For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.

<em>Your question is not complete, but most probably your full questions was</em>

<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>

Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.

Learn more about intermediate value theorem here:

brainly.com/question/28048895

#SPJ4

4 0
1 year ago
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