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Tanya [424]
3 years ago
15

Find p(1) if the polynomial is p (X)=x2-3x+6​

Mathematics
1 answer:
sveticcg [70]3 years ago
8 0

Step-by-step explanation:

hope it helps you..........

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7(2+5v)=3v+14 can anyone help???
arsen [322]
7(2+5v)=3v+14
14+35v=3v+14
-3v -3v
14+32v=14
-14 -14
32v=0
÷32 ÷32
v=0

hope this helps!!
5 0
3 years ago
Read 2 more answers
1. What is the arithmetic mean of the numbers 14,16,18,5,17 ?
Basile [38]
Number 2 is 20 number 3 is 11
5 0
3 years ago
Read 2 more answers
30 POINTS AVAILABLE
kherson [118]

Answer:

\large\boxed{(x-2)^2+(y-1)^2=34}

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

Substitute:

h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points (2, 1) and (5, -4):

r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}

Finally we have:

(x-2)^2+(y-1)^2=(\sqrt{34})^2

3 0
3 years ago
What is the reciprocal of 3^-2 ?​
weqwewe [10]

Answer:

1/3^2

Im trying to earn my brainliest..so if you don't mind :)

8 0
3 years ago
Find the domain and range of the relation: {(–20, 11), (6, –8), (1, –20), (–13, 13)}
user100 [1]

Answer:

D: {-20, -13, 1, 6}

R: {-20, -8, 11, 13}

Step-by-step explanation:

Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.

Therefore:

Domain: {-20, -13, 1, 6}

Range: {-20, -8, 11, 13}

4 0
3 years ago
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