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3 years ago

If a=1 b=2 c=3 find the value of 4a3b2

Mathematics

2 answers:

Dima020 [189]3 years ago

7 0

Answer:

Step-by-step explanation:

We just need to put in the values of a and b.

4a3b² = 4(1) × 3(2)²

= 4 × 3(4)

= 4 × 12

= 48

BaLLatris [955]3 years ago

3 0

Answer:

Step-by-step explanation:

a4=4

3b=2 x 3=6

2c=2 x 3=6

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What is the simplified form of 12x/900x²y4z6?

zalisa [80]

Answer:

$360xy^2|xz^3|$

Step-by-step explanation:

Given expression:

$12x \sqrt{900x^2y^4z^6}$

$\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:$

$\implies 12x \sqrt{900}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

Replace 900 with 30² :

$\implies 12x \sqrt{30^2}\sqrt{x^2}\sqrt{y^4}\sqrt{z^6}$

$\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:$

$\implies 12x \cdot 30|x|\sqrt{y^4}\sqrt{z^6}$

$\implies 360x|x|\sqrt{y^4}\sqrt{z^6}$

(We need to use the absolute value of √x² since the x term was originally to the power of 2, which means the value of x² is always positive since the exponent is even).

$\textsf{Apply exponent rule} \quad \sqrt{a^m}=a^{\frac{m}{2}}:$

$\implies 360x|x|\cdot y^{\frac{4}{2}}\cdot z^{\frac{6}{2}}$

Simplify:

$\implies 360xy^2|xz^3|$

(We need to use the absolute value of z³ since the z term was original to the power of 6, which means the value of z⁶ is always positive since the exponent is even).

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2 years ago

What is the solution to y=x+16 and y=-x+4??

BaLLatris [955]

<span>y=x+16
y=-x+4

All you have to do is substitute.
Put the second equation into the first equation.

-x + 4 = x + 16
4 = 2x + 16
-12 = 2x
-6 = x

Now substitute the x into one of the equations to get y.

y = (-6) + 16
y = 10

The solution to these equations is (-6, 10).</span>

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4 years ago

Whats this answer i need it fast uwu

IrinaVladis [17]

Find slope (y2-y1)/(x2-x1)
Pick points: (1,10) , (2,8)
(8-10)/(2-1) = -2/1 = -2
Y = -2x + b
10 = -2 + b, b = 12
It would be the first response
12 = initial while -2 is rate of change

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sweet-ann [11.9K]

Answer: can you explain it more?

Step-by-step explanation:

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