Will 5 1/5 x 2/5 be larger or smaller than 5 1/5

A researcher is exploring the notion that there is an economy of scale in raising children. While having one child might add to

trasher [3.6K]

Answer:

The probability is $G = 85%$

Step-by-step explanation:

From the question we are told that

The percentage of parents that have one child under 18 in their homes is k = 15%

The percentage of parents that have two children is T = 65%

The percentage of parents that have three or more children is Y = 20%

Generally the probability that any given family who is selected have two or more children at home is mathematically evaluated as

$G = T + Y$

=> $G = 65% + 20%$

=> $G = 85%$

4 0

3 years ago

38600 mg = n dag what does n equal???

Vlad [161]

Answer:
n = 3.68

Explanation:
We know that:
1 mg is equivalent to 0.0001 dag
To convert 38600 mg to dag, we will simply use cross multiplication as follows:
1 mg ..............> 0.0001 dag
38600 mg ......> n

n = (38600*0.0001) / 1
n = 3.68

Hope this helps :)

3 0

3 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago

many villages have water tanks that they use for farming Jeffs Village has a cylinder shaped water tank that has a 4M radius and

Alex73 [517]

Answer:

8Mm-18M

Step-by-step explanation:

the volume is 8Mm-18M

6 0

3 years ago

Read 2 more answers

5)

Paladinen [302]

Answer:183.4

Step-by-step explanation:

90/11=8.181818 1500/8.1818 = ≈183.4 time you would roll six

6 0

3 years ago