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4 years ago

Do you think that solids can undergo convection

1 answer:

7 0

<span>Convection means the movement happens inside a fluid by the cause of too much heat and lesser density to rise, and also the colder cause denser materials to sink.
Thus, Solid cannot undergo convection because the molecules inside the solid are closer and can hardly move unlike liquid.
So, when the temperature got hotter or colder, the molecules on solid will only vibrate and not convert.
Therefore, this concludes that the solid do not undergo convection rather conduction of heat.</span>

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Consider that a clay model of a tiger has a mass of 0.195 kg and glides on ice at a speed of 0.75 m/s. It hits another clay mode

juin [17]

Answer:

The final velocity after the collision is 0.27 m/s.

Explanation:

Given that,

Mass of tiger, m = 0.195 kg

Initial speed of tiger model, v = 0.75 m/s

Mass of another clay model, m' = 0.335 kg

Initially, second model is at rest, v' = 0

We need to find the final velocity after the collision. It is a case of inelastic collision. Using the conservation of linear momentum as :

$mv+m'v'=(m+m')V\\\\V=\dfrac{mv+m'v'}{(m+m')}\\\\V=\dfrac{0.195\times 0.75}{(0.195 +0.335 )}\\\\V=0.27\ m/s$

So, the final velocity after the collision is 0.27 m/s.

6 0

4 years ago

Where is the most energy transferred in a food web?

Alla [95]

Answer:

is b and d hope id helpful

Explanation:

idk how to explain

6 0

4 years ago

What is potential energy?

iVinArrow [24]

energy associate with position or shape

5 0

4 years ago

1. An electron (Q=16x10^-20 C, m=1x10^-30 kg) moving at half a megameter per second up the page enters a region with a uniform m

jek_recluse [69]

Explanation:

It is given that,

Charge on electron, $q=16\times 10^{-20}\ C$

Mass of the electron, $m=9.1\times 10^{-31}\ kg$

Speed of the electron, $v=0.5\ Mm/s=0.5\times 10^6\ m/s$

Magnetic field, B = 1 T (directed out of the page)

Let F is the magnetic force acting on the electron. It is given by :

$F=qvB\ sin\theta$

Here, $\theta=90^{\circ}$

$F=qvB$

$F=16\times 10^{-20}\ C\times 0.5\times 10^6\ m/s\times 1\ T$

$F=8\times 10^{-14}\ N$

Using the right hand rule, the direction of magnetic force is upward to the plane of the paper. Also, the electron will follow the circular path. It is given by :

$r=\dfrac{mv}{qB}$