C :) cause a direction has nothing do do with velocity !
The average velocity can be calculated from the slope of the graph
Explanation:
In a position-time graph, the position is represented on the y-axis while the time is represented on the x-axis.
The slope of the graph is given by:
![m=\frac{\Delta y}{\Delta x}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B%5CDelta%20y%7D%7B%5CDelta%20x%7D)
where
is the change in the y-variable
is the change in the x-variable
However, we have:
corresponds to the change in position, therefore it is the displacement
corresponds to the change in time
This means that the slope can be rewritten as
![m=\frac{displacement}{time}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7Bdisplacement%7D%7Btime%7D)
However, this ratio corresponds to the definition of average velocity:
![velocity = \frac{displacement}{time}](https://tex.z-dn.net/?f=velocity%20%3D%20%5Cfrac%7Bdisplacement%7D%7Btime%7D)
Therefore, the slope of a position-time graph gives the average velocity.
Learn more about velocity:
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The fundamental frequency of a standing wave which has
string of length L
mass per unit meu
has the tension T
is given by f = 1/2L![\sqrt{T/meu}](https://tex.z-dn.net/?f=%5Csqrt%7BT%2Fmeu%7D)
Now we are required to find if the tension is doubled, with all other factors held constant, what will be the effect on the fundamental frequency
According to the formula,
the fundamental frequency f is directly proportional to the factor of square root
Hence when the tension is doubled while other factors remaining constant
the formula will become
f= 1/2L![\sqrt{2T/meu}](https://tex.z-dn.net/?f=%5Csqrt%7B2T%2Fmeu%7D)
Hence the change in the fundamental frequency will be of the factor ![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
Therefore, the change will be of ![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
Disclaimer: the question has missing part 1 and part 2 and hence part 3 has been answered
For further reference:
brainly.com/question/20732973?referrer=searchResults
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