Question

a student is pushing a 50 kilogram cart with a force of 500 newtons another students measures the speed of the cart and finds that the cart is only accelerating a 4 m/s how much friction must be acting on the cart

Answer 1

The force of friction is 300 N

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. So we can write

$\sum F = ma$

where

$\sum F$ is the net force acting on the object

m is its mass

a is its acceleration

For the cart in this problem, we have two forces acting on it:

- The force of push, F = 500 N, forward

- The force of friction, $F_f$, backward

So Newton's second law can be rewritten as

$F-F_f = ma$

where

m = 50 kg

$a=4 m/s^2$ is the acceleration of the cart

And solving for $F_f$, we find the force of friction:

$F_f = F-ma=500-(50)(4)=300 N$

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