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Dominik [7]
3 years ago
15

6) What is the value of digit 7 in 0.057 *.///what is the answer _____________________

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

7/1000 thousandths for place value

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Help me.what is the answer?
kolbaska11 [484]

Answer:

I believe its 1.5

Step-by-step explanation:

Hope it helps srry if im wrong.

3 0
3 years ago
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The charge for ice skating is $3 for the skate rental and and 2 per hour to skate how much will you pay if you skate
Semenov [28]
The answer is 6

2×3=6
6 0
2 years ago
I need help with this please.
LenaWriter [7]

Answer:

k = 3

Step-by-step explanation:

0 • 3 = 0

1 • 3 = 3

2 • 3 = 6

3 • 3 = 9

4 • 3 = 12

Notice the x value times 3 is the y value. Therefore, k is 3. Let me know if I got anything wrong. I hope this helps!

4 0
3 years ago
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What is the correct justification for the indicated steps?
yanalaym [24]

The given proof of De Moivre's theorem is related to the operations of

complex numbers.

<h3>The Correct Responses;</h3>
  • Step A: Laws of indices
  • Step C: Expanding and collecting like terms
  • Step D: Trigonometric formula for the cosine and sine of the sum of two numbers

<h3>Reasons that make the above selection correct;</h3>

The given proof is presented as follows;

\mathbf{\left[cos(\theta) + i \cdot sin(\theta) \right]^{k + 1}}

  • Step A: By laws of indices, we have;

\left[cos(\theta) + i \cdot sin(\theta) \right]^{k + 1} = \mathbf{\left[cos(\theta) + i \cdot sin(\theta) \right]^{k} \cdot \left[cos(\theta) + i \cdot sin(\theta) \right]}

\left[cos(\theta) + i \cdot sin(\theta) \right]^{k} \cdot \left[cos(\theta) + i \cdot sin(\theta) \right] =  \mathbf{\left[cos(k \cdot \theta) + i \cdot sin(k \cdot \theta) \right] \cdot \left[cos(\theta) + i \cdot sin(\theta) \right]}

  • Step B: By expanding, we have;

\left[cos(k \cdot \theta) + i \cdot sin(k \cdot \theta) \right] \cdot \left[cos(\theta) + i \cdot sin(\theta) \right] = cos(k \cdot \theta) \cdot cos(\theta) - sin(k \cdot \theta) \cdot sin(\theta) + i  \cdot \left [sin(k \cdot \theta) \cdot cos(\theta) + cos(k \cdot \theta) \cdot sin(\theta) \right]

  • Step D: From trigonometric addition formula, we have;

cos(A + B) = cos(A)·cos(B) - sin(A)·sin(B)

sin(A + B) = sin(A)·cos(B) + sin(B)·cos(A)

Therefore;

cos(k \cdot \theta) \cdot cos(\theta) - sin(k \cdot \theta) \cdot sin(\theta) + i  \cdot \left [sin(k \cdot \theta) \cdot cos(\theta) + cos(k \cdot \theta) \cdot sin(\theta) \right] = \mathbf{ cos(k \cdot \theta + \theta) + i \cdot sin(k \cdot \theta  + \theta)}

Learn more about  complex numbers here:

brainly.com/question/11000934

4 0
2 years ago
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3. If dy = x^2y^2 , then what is d2y/dx2
lakkis [162]

\text{Given that,}\\\\\dfrac{dy}{dx} = x^2 y^2\\\\ \implies \dfrac{d^2 y}{dx^2} = x^2\cdot  2y \dfrac{dy}{dx}+ y^2 \cdot 2x\\\\\implies \dfrac{d^2 y}{dx^2} = x^2 \cdot  2y \cdot x^2 y^2  +2xy^2\\\\\implies \dfrac{d^2 y}{dx^2} =2x^4y^3 + 2xy^2 = 2xy^2(x^3y+1)

5 0
2 years ago
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