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algol13
3 years ago
7

Work out (3.6 times 10^-5) divided by (1.8 times 10^2) Give your answer in simplest form.

Mathematics
1 answer:
romanna [79]3 years ago
4 0

Answer:

( 3.6 × 10 ^-5 ) ÷ ( 1.8 × 10² ) = 2 × 10^-7

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Pls help I’ll brainlest ASAP <br><br><br> Make this sentence better the building is old and ugly
Elden [556K]

Answer:

the building is aged and unique.

6 0
2 years ago
In the diagram below of triangle EFG, H is a midpoint of EF and J is a midpoint
Korolek [52]

Answer:

14

Step-by-step explanation:  2(4x+6)=

\,\,34-3x

34−3x

Since HJ is a midsegment, twice HJ is equal to EG.

8x+12=

8x+12=

\,\,34-3x

34−3x

Distribute.

8x+12=

8x+12=

\,\,-3x+34

−3x+34

Communicative property to change the order

\color{red}{+3x}\phantom{+12}\phantom{=}

+3x+12=

\,\,\color{red}{+3x}\phantom{+34}

+3x+34

+3x to both sides.

11x+12=

11x+12=

\,\,34

34

\phantom{11x}\color{red}{-12}\phantom{=}

11x−12=

\,\,\color{red}{-12}

−12

-12 to both sides.

11x=

11x=

\,\,22

22

\frac{11x}{11}=

11

11x

​  

=

\,\,\frac{22}{11}

11

22

​  

 

Divide both sides by 11

x=

x=

\,\,2

2

Value of x

HJ=

HJ=

\,\,4x+6

4x+6

Value of HJ

HJ=

HJ=

\,\,4(2)+6

4(2)+6

Plug in x.

HJ=

HJ=

\,\,8+6

8+6

Multiply.

HJ=

HJ=

\,\,14

14

8 0
3 years ago
1+4=5<br> 2+5=12<br> 3+6= 21<br> 8+11= ?
saul85 [17]
8+11=19 but if you add 21+19+12+5=57.
7 0
3 years ago
Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8?
vovangra [49]

Answer: x≤ -0.5

Step-by-step explanation:  Graph the two lines or solve for x:

2x – 6 ≥ 6(x – 2) + 8

2x – 6 ≥ 6x – 12 + 8

2x – 6 ≥ 6x – 4

-4x  ≥  2

  x  ≤  -1/2  [Inequality is reversed when multiplying or dividing by a negative number]

The number line is anything less than or equal to - 1/2

Or one can plot each side of the inequality and note the interception point (x = -(1/2)).

4 0
2 years ago
6 points
kodGreya [7K]

Answer:

y=-2\,(x+3)^2-3

Step-by-step explanation:

Notice that they are asking you to write the equation of the parabola in vertex form, that is using the coordinates of the vertex (x_v,y_v) in the expression:

y-y_v=a\,(x-x_v)^2\\y=a\,(x-x_v)^2+y_v

we can start by directly replacing the given vertex coordinates (-3, -3) in the expression, and then using the extra info on the point the parabola goes through in order to find the parameter a:

y=a\,(x-x_v)^2+y_v\\y=a\,(x+3)^2+(-3)\\y=a\,(x+3)^2-3\\-5=a\,(-2+3)^2-3\\-5=a\,(1)-3\\a=-5+3\\a=-2

So, now we can write the full expression for the parabola:

y=a\,(x+3)^2-3\\y=-2\,(x+3)^2-3

8 0
3 years ago
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