So you can actually use a couple trig identities
tan(x-a) =(tan x-tan a)/(1+tan x*tan a)
From there, easy!
(tan x-tan a)/(tan x-tan a)/(1+tan x*tan a)
1/1/(1+tan x*tan a)
which is
(1+tanx*tana)
1+tan^2a
sec^2 a
typo, forgot the 1/1
Answer =1:15.
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Youre gonna need to reupload with a picture
Answer:
16
Step-by-step explanation:
4+4=8
8+8=16