That would be x=-8 as it asks for a ventricle line.
![\bf \cfrac{4a}{3}-\cfrac{b}{4}=6 \qquad \qquad \cfrac{5a}{6}+b=13 \\\\\\ \textit{let us remove the denominators off those folks}\\ \textit{by multiplying the first one by 12, both sides}\\ \textit{and the second one by 6, both sides, thus} \\\\\\ 12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72 \\\\\\ 6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B4a%7D%7B3%7D-%5Ccfrac%7Bb%7D%7B4%7D%3D6%0A%5Cqquad%20%5Cqquad%20%0A%5Ccfrac%7B5a%7D%7B6%7D%2Bb%3D13%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Blet%20us%20remove%20the%20denominators%20off%20those%20folks%7D%5C%5C%0A%5Ctextit%7Bby%20multiplying%20the%20first%20one%20by%2012%2C%20both%20sides%7D%5C%5C%0A%5Ctextit%7Band%20the%20second%20one%20by%206%2C%20both%20sides%2C%20thus%7D%0A%5C%5C%5C%5C%5C%5C%0A12%5Cleft%28%20%5Ccfrac%7B4a%7D%7B3%7D-%5Ccfrac%7Bb%7D%7B4%7D%20%5Cright%29%3D12%286%29%5Cimplies%2016a-4b%3D72%0A%5C%5C%5C%5C%5C%5C%0A6%5Cleft%28%20%5Ccfrac%7B5a%7D%7B6%7D%2Bb%20%5Cright%29%3D6%2813%29%5Cimplies%205a%2B6b%3D78)
![\bf \textit{now, let's do the elimination} \\\\ \begin{array}{llll} 16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\ 5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\ &&--------\\ &&58a+0\quad=372 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%20%5Ctextit%7Bnow%2C%20let%27s%20do%20the%20elimination%7D%0A%5C%5C%5C%5C%0A%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A16a-4b%3D72%26%5Cboxed%7B%5Ctimes%203%7D%5Cimplies%20%2648a-%5Cunderline%7B12b%7D%3D216%5C%5C%5C%5C%0A5a%2B6b%3D78%26%5Cboxed%7B%5Ctimes%202%7D%5Cimplies%20%2610a%2B%5Cunderline%7B12b%7D%3D156%5C%5C%0A%26%26--------%5C%5C%0A%26%2658a%2B0%5Cquad%3D372%0A%5Cend%7Barray%7D)
solve for "a", once you get "a", plug it back into either equation to get "b"
For this question you can say:
16g - 48g = -32g
and 32h - 40h = -8h
so you will have:
-32g - 8h and you can factor -8 so you will have:
-8(4g + h) :)))
i hope this is helpful
have a nice day