Answer:
The height of the rocket at 3 seconds is 270 feet
Step-by-step explanation:
To calculate the height of the rocket at 3 seconds,
First, we will determine the height the rocket has traveled in 3 seconds
The height traveled by the rocket is given by
Height (h) = Velocity (v) × Time (t)
From the question,
The rocket travels 85 feet per second, that is the velocity of the rocket is 85 feet per second,
Now,
v = 85 feet / second
t = 3 seconds
Hence,
Height (h) = 85 feet /second × 3 seconds
Height = 255 feet
∴ the rocket would have traveled 255 feet in 3 seconds,
But, the rocket starts on a launch pad 15 feet of the ground,
Then, the height of the rocket at 3 seconds is
255 feet + 15 feet = 270 feet.
Hence, the height of the rocket at 3 seconds is 270 feet
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and the solutions are decreasing functions.