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vladimir1956 [14]
3 years ago
6

How do you find ratio

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0
<span>Identify the known ratio and the unknown ratio.Set up the proportion.Cross-multiply and solve.Check answer by plugging result into unknown ratio. Look here for the formula: </span>http://prntscr.com/e0qtq3
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Write an expression showing 5 less than the number K
BigorU [14]

Answer:

k-5

Step-by-step explanation:

5 0
3 years ago
Help soon please! I need to get done soon
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

Two Decimal places

.9(29.3) = 26.37

18(5.75)= 103.50

Three Decimal places

3.21(2.4) = 7.704

50.7(14.06)= 712.842

Four Decimal places

4.2(.938)= 3.9396

.48(12.19)= 5.8512

8 0
3 years ago
in klm the measure of m=90 the measure of l=68 and mk=2.5 feet. find the length of kl to the nearest tenth of a foot
frutty [35]

Answer:

2.7

Step-by-step explanation:

5 0
2 years ago
Please help me guys​
seraphim [82]

Area of pond:

A=\pi r^{2}

r=1,5m

A=3,142*1,5*1,5=7,0695

Area of pond with path

B=\pi r^{2}

r=50 cm+1,5m=0,5m+1,5m=2m

B=3,142*2*2=12,568

Area of path:

12,568-7,0695=5,4985=5,50

8 0
3 years ago
Read 2 more answers
A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
ivann1987 [24]

Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0
4 years ago
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