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vladimir1956 [14]
3 years ago
6

How do you find ratio

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0
<span>Identify the known ratio and the unknown ratio.Set up the proportion.Cross-multiply and solve.Check answer by plugging result into unknown ratio. Look here for the formula: </span>http://prntscr.com/e0qtq3
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PLZZZ HELP 30 POINTS!!!!!!!
djverab [1.8K]

Answer:

150

Step-by-step explanation:

150

6 0
2 years ago
Can you guys help me please<br><br>QUICKLY
Gwar [14]

Answer:

Answer is 2x2x3x7

Step-by-step explanation:

2x2=4

4x3=12

12x7=84

5 0
3 years ago
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X+58=6 what is the value of x
bulgar [2K]
The answer would be negative fifty two 
-52

X+58=6
58-6=52
So the answer would be negative 52
5 0
3 years ago
According to a​ survey, 60 ​% of the residents of a city oppose a downtown casino. Of these 60 ​% about 8 out of 10 strongly opp
katrin [286]

Answer:

(a) 0.48

(b) 0.20

(c) it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

Step-by-step explanation:

​(a) Find the probability that a randomly selected resident opposes the casino and strongly opposes the casino. ​

The probability that a radomly selected resident opposes the casino and strongly opposes the cassino is the product of the two probabilities, that a resident opposes the casino and that it strongly opposes the casino (once it is in the first group) as it is shown below.

Use this notation:

  • Probability that a radomly selected resident opposes the casino: P(A)

  • Probability that a resident who opposes the casino strongly opposes it: P(B/A), because it is the probability of event B given the event A

i) Determine the <em>probability that a radomly selected resident opposes the casino</em>, P(A)

Probability = number of favorable outcomes / number of possible outcomes

  • P(A) is <em>given as 60%</em>, which in decimal form is 0.60

ii) Next, determine,the <em>probability that a resident who opposes the casino strongly opposes it</em>, P(B/A):

  • It is given as 8 out of 10 ⇒ P(B/A) = 8/10

iii) You want the probability of both events, which is the joint probability or  intersection: P(A∩B).

So, you can use the definition of conditional probability:

  • P(B/A) = P(A∩B) / P(A)

iv) From which you can solve for P(A∩B)

  • P(A∩B) = P(B/A)×P(A) =  (8/10)×(0.60) = 0.48

(b) Find the probability that a randomly selected resident who opposes the casino does not strongly oppose the casino.

In this case, you just want the complement of the probability that <em>a radomly selected resident who opposes the casino does strongly oppose the casino</em>, which is 1 - P(B/A) = 1 - 8/10 = 1 - 0.8 = 0.2.

​(c) Would it be unusual for a randomly selected resident to oppose the casino and strongly oppose the​ casino?

You are being asked about the joint probability (PA∩B), which you found in the part (a) and it is 0.48.

That is almost 0.50 or half of the population, so you conclude it is not unusual for a radomly selected resident to oppose the casino and strongly oppose the​ casino.

8 0
3 years ago
I need help with this please
andrezito [222]

Answer:

1988920000000000

Step-by-step explanation:

1.98892 x 1000000000000000 (15 zeros)

The upper number (in this case 15) indicates the amount of zeros after the 1 (10 is 10^1, 100 is 10^2)

7 0
3 years ago
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