First, let's turn all the numbers into improper fractions so that we can find the answer easier.
-2
= r - 
-
= r - 
Now we have to isolate 'r'.
First, we have to make sure that the variable is on one side and all the numbers are on the other side.
To do this, we have to add
to both sides.
In order to do this, we need to ensure that both fractions have a common denominator.
-
= r - 
Ensure that the denominators are the same:
= r - 
+
= r
= r
Good luck!
So, first we multiply the fraction by using the formula a/b times c/d= a times c/b times d
=(y^2-16) times 5y/2y(y-4)
Now, we cancel the common factor y
=(y^2-16) times 5/2(y-4)
Now, we factor 5(y^2-16)
We factor (y^2-16) first
y^2-16
Rewrite 16 as 4^2
y^2-4^2
Now, apply the formula x^2-y^2=(x+y)(x-y)
=y^2-4^2=(y+4)(y-4)
=5(y+4)(y-4)
=5(y+4)(y-4)/2(y-4)
Cancel the common factor y-4
=5(y+4)/2
Answer: 5(y+4)/2
Answer:9
Step-by-step explanation:when an absolute value has a negative it turns to a positive which makes this problem 3x3
Answer:
D. 2 1/6
Step-by-step explanation:
To visualize the problem easier, start by converting all the fractions to improper fractions, this will allow you to just add the denominators and simplify the question:
1/6, 5/6, 1 3/6 —> 1/6, 5/6, 9/6
Now that the sequence is rewritten, you can simply add 4 to the numerator, which equals 13/6.
Rewrite this again by finding how many times 6 goes into 13, and use the remainder as the numerator of the new fraction, which will end up as 2 1/6.