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Assoli18 [71]
3 years ago
8

Evaluate the expression for x=5, y=-3 and z=7 7 - 3y – 3z

Mathematics
2 answers:
andrew11 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

7 - 3(-3) - 3(7) = 7 + 9 - 21 = 16 - 21 = -5

barxatty [35]3 years ago
5 0

Answer:

-5

Step-by-step explanation:

(Refer to image)

Plug in the y and z and use order of operations to simplify!

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What is the length of BC⎯⎯⎯⎯⎯ ?<br><br><br> Enter your answer in the box.
Rudiy27

Answer:

  \overline{\text{BC}}=\boxed{22}

Step-by-step explanation:

The angle marks mean those angles have the same measure. That means the sides opposite them have the same measure, so ...

  2x -24 = x -2

  x = 22 . . . . . . . . . add 24-x

The length of BC is x, so is 22.

BC = 22

8 0
3 years ago
Please help.
Leona [35]

Answer:

1. 500

2. 2,286

Step-by-step explanation:

1. $250 divide by 0.5

2. 762 times by 3

4 0
3 years ago
Read 2 more answers
What is the simplest form of 12/60
ladessa [460]
1/5 
because if you divide it by 12, 1/5 will be your answer
8 0
3 years ago
Read 2 more answers
What is the slope of any line perpendicular to y=-1/3x+22
STatiana [176]
Answer:
The slope of any line perpendicular to the given line is 3

Explanation:
The general form of the linear line is:
y = mx + c where m is the slope
The given line is:
y = -1/3 x + 22
Comparing the given line with the general form, we will find that:
slope of the given line (m1) is -1/3

Now, for any two lines to be perpendicular, the product of their slopes should be equal to -1.
This means that:
m1 * m2 = -1
We have m1 = -1/3
Therefore:
-1/3 * m2 = -1
m2 = 3*1
m2 = 3

Hope this helps :)
5 0
3 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
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