Answer:
$10 bill = 14 and $20 bill = 16.
Step-by-step explanation:
Given : A cashier has 30 bills, all of which are $10 or $20 bills. The total value of the money is $460.
To find : How many of each type of bill does the cashier have.
Solution : We have given that
A cashier has 30 bills
Let bill of $10 = x .
Bill of $20 = y .
Money of $10 = 10x .
Money of $20 = 20y.
Total bill
x + y = 30-------(1)
10x + 20y = 460-----(2)
On multiplying equation 1 by 10 and subtracting from equation 2.
10x + 20 y = 460
(-)10x +(-) 10 y = (-)300
______________
0 + 10 y = 160 .
On dividing by 10
y = 16 .
Plug y = 16 in equation 1
x + 16 = 30
On subtracting both sides by 16.
x = 30 - 16.
x = 14
Therefore, $10 bill = 14 and $20 bill = 16.
R+5=8 is the corrects answer
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Easy ! you first subtract the 5 to itself and to the 17, so 5 - 5 and 17 - 5. your equation should look like 3g = 12. since we need to isolate the variable (g) we need to divide 3 by itself and 12 by 3, so 3 ÷ 3 and 12 ÷ 3. now you have g = 4!
32-x=0; with x equaling the amount descended or -32.
