Question

A soup company puts 12 ounces of soup in each can. The company has determined that 97% of cans have the correct amount. Which of the following describes a binomial experiment that would determine the probability that a case of 36 cans has all cans that are properly filled?
a. n=36, p=0.97, x=1
b. n=12, p=0.36, x=97
c. n=12, p=0.97, x=0
d. n=36, p=0.97, x=36

Answer 1

Answer:

Option d: n = 36, p = 0.97, x = 36.

Step-by-step explanation:

We are given that a soup company puts 12 ounces of soup in each can. The company has determined that 97% of can have the correct amount.

We have to describe a binomial experiment that would determine the probability that a case of 36 cans has all cans that are properly filled.

Let X = Number of cans that are properly filled

The above situation can be represented through binomial distribution;

$P(X = x) = \binom{n}{x} \times p^{x} \times (1-p)^{n-x} ; x = 0,1,2,........$

where, n = number of trials (samples) taken = 36 cans

            x = number of success = all cans are properly filled = 36

            p = probabilitiy of success which in our question is probability that

                  can have the correct amount, i.e. p = 97%

So, X ~ Binom (n = 36, p = 0.97)

Hence, from the options given the correct option which describes a binomial experiment that would determine the probability that a case of 36 cans has all cans that are properly filled is n = 36, p = 0.97, x = 36.