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Llana [10]
3 years ago
8

How do you determine the difference in time between the arrival of the primary (P) wave and the arrival of the secondary (S) wav

e during an earthquake? (In other words, how do you determine T?)
Biology
2 answers:
alexandr1967 [171]3 years ago
8 0
I believe that the seismograph shows the difference of time between the arrival of the two types of waves and this can be read right off the seismograph recording. Also, to get the distance of the earthquake from the recording spot one can derive the average velocity from Vp x Vs/Vp-Vs=km/sec x difference in time of arrival of the two equals the distance to the epicentre, This is where Vp = velocity of P wave and Vs = velocity of S waves. 
iVinArrow [24]3 years ago
3 0

Answer:

C!!!!

Explanation:

Subtract the P from the S wave

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In what kind of cells would you expect to see the most mitochondria?
Basile [38]

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Explanation:

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imagine that ou are stduying a very large population of moths that is isolate d from gene flow.A single gene controls wing color
algol [13]

About the question:

I failed to find the complete question. However, I will explain why this population is considered to be in Hardy-Weinberg equilibrium, and what the destiny of the alleles is.  

Answer:

This population is in equilibrium because it accomplishes all the H-W assumptions for a population in equilibrium. Genetic nor allelic frequencies will change generation after generation. Alleles will remain equal.

Explanation:

Available data:

  • A single gene controls wing color
  • Half of the moths have white-spotted wings
  • half of the moths have plain brown wings
  • W allele is dominant and expresses white wings
  • w allele is recessive and expresses brown wings
  • Individuals mate randomly
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We will know by theory if this population is or is not in equilibrium Hardy-Weinberg if the population is in concordance with the assumptions of the theory. So let us first analyze the Hardy-Weinberg assumptions for a population in equilibrium:

•  <em>Random matings:</em> Any individual get crossed with any other individual

•  <em>No superposed generations:</em> each individual can leave their gametes in the pool only once.

•  <em>No mutations: </em>No mutations originate any new gametes.

•  <em>No migration: </em>No incorporation of gametes from other populations.

•  <em>Infinite population size:</em> the probabilities of randomly taking an A gamete from the pool are p, and the probability of taking a B gamete is q.

•  <em>No natural selection:</em> Each individual has equal surviving and reproducing probabilities as any other, contributing proportionally to the gamete pool.

So, the exposed population

- is isolated, meaning that there is no gene flow from other populations. No new genes will be introduced.

- has no mutations, so no allele will change to express a new form

- individuals mate randomly

- there is no natural selection acting on this group as an evolutive force that might alter the equilibrium.

Genetic nor allelic frequencies will change generation after generation.

In a Hardy-Weinberg population, where allelic frequencies are p and q (assuming a diallelic gene), genotypic frequencies after one generation of random matings are p², 2pq and q². The allelic frequencies, as well as the genotypic frequencies, remain equal after successive generations. Alleles will remain in the population from many generations.  

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This process is called <span>Peristalsis.

</span>
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