Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Answer:
$16.
Step-by-step explanation:
Let t represent the cost of each tree.
We have been given that Yuri purchased 8 trees to have planted at his house. So the cost of 8 trees will be 8t.
We are also told that the store charged a delivery fee of $5 per tree. So the delivery charges of 8 trees will be 
The total cost of purchasing 8 trees will be 
.
Since the total cost of the trees including the delivery was $168, so we can get an equation as:
Upon dividing both sides of our given equation by 8, we will get:
Therefore, the cost of each tree is $16.
50,000 is the nearest ten thousand.
Answer:
3x(x-1)-5(x-1)
=3x²-3x-5x+5 (we can count it one by one)
=3x²-8x+5 (we can calculate the same variable)
#i'm from indonesia
hope it helps.
The answer is X=23 and y=9
