Math help please show work I will make brainlist if correct thanks

How do you graph this y-2x=0 y=4x+3

Svetlanka [38]

Answer:

Step-by-step explanation:

those are 2 lines, and to graph them find 2 points for each to draw a line trough them

line 1

y-2x=0 so y=2x

pick any value for x

(x=1, y=2*1=2), (x=3, y=2*3=6)

Draw a line trough points (1,2) and (3,6)

line 2

y=4x+3

(x=1, y=4*1+3=7), (x= -1, y= 4(-1)+3= -1)

Draw a line trough points (1,7) and (-1, -1)

5 0

3 years ago

How many labeled points are between points B and U? CU four zero two seven

RoseWind [281]

Answer:

(A) zero points .

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Paige has 3 coats: a pink one, a red one, and a white one. She has a black scarf, a gray scarf and 1 set of white gloves. Determ

IRISSAK [1]

Hi there, again! Hopefully this helps, again!

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Since she has 3 coats, 2 scarfs, and 1 glove:

She has 6 ways to choose a coat, a scarf, and a glove(s).

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My 6 combinations:

1.) Red coat, black scarf, white glove(s).

2.) White coat, grey scarf, white glove(s).

3.) Pink coat, black scarf, white glove(s).

4.) Red coat, grey scarf, white glove(s).

5.) White coat, black scarf, white glove(s).

6.) Pink coat, grey scarf, white glove(s).

5 0

4 years ago

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Find the probability that in five tosses of a fair die, a 3 will appear (a) twice, (b) at most once, (c) at least two times.

Jobisdone [24]

Answer:

A) 0.1612

B) 0.8031

C) 0.1969

Step-by-step explanation:

For each toss of the die, there are only two possible outcomes. Either it is a 3, or it is not. The probability of getting a 3 on each toss is independent from other tosses. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

Five tosses, so $n = 5$

The die has 6 values, from 1 to 6. The die is fair, so each outcome is equally as likely. The probability of a 3 appearing in a single throw is $p = \frac{1}{6} = 0.167$