Answer:
The radius of the sphere is 4.05 m
Explanation:
Given;
potential at surface,
= 450 V
potential at radial distance,
= 150
radial distance, l = 8.1 m
Apply Coulomb's law of electrostatic force;


Therefore, the radius of the sphere is 4.05 m
The newton is the SI unit for force; it is equal to the amount of net force required to accelerate a mass of one kilogram at a rate of one meter per second squared.
Gravitational force is a non-contact force.