Answer:
6 km/h
Explanation:
V avg = ∆x/∆t = 3km / 30 min ×(60min/1h) = 3 km× 2 /h = 6 km/h
Answer:
(A) Angular speed 40 rad/sec
Rotation = 50 rad
(b) 37812.5 J
Explanation:
We have given moment of inertia of the wheel 
Initial angular velocity of the wheel 
Angular acceleration 
(a) We know that 
We have given t = 2 sec
So 
Now 
(b) After 3 sec 
We know that kinetic energy is given by 
Answer:
Force is classified as a push or a pull
Explanation:
The total momentum of the system is equal to 50 Kgm/s.
<u>Given the following data:</u>
To determine the total momentum of the system:
Mathematically, momentum is given by the formula;

<u>For Football player 1:</u>

Momentum 1 = 160 Kgm/s.
<u>For Football player 2:</u>

Momentum 1 = 210 Kgm/s.
Now, we can calculate the total momentum of the system:

Total momentum = 50 Kgm/s.
<u>Note:</u> We subtracted because the football players were moving in opposite directions.
Read more: brainly.com/question/15517471
Answer: Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged). If an atom gains or loses one or more electrons, it becomes an ion.