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Bas_tet [7]
4 years ago
6

Julie Meyer is the manger for Ace trucking company.during December she worked 165 hours earning 27 an hour.what was her straight

-time pay for December? please help me
Mathematics
2 answers:
OlgaM077 [116]4 years ago
8 0
The answer is 4,455. 27×165=4,455.
Travka [436]4 years ago
8 0
I think it is 4,455. 27×165=4,455.
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✓-90= Ai√B<br> What is the value of A?<br> What is the value of B?
olga2289 [7]

Answer:

A = 3, B = 10

Step-by-step explanation:

\sqrt{-90}

= \sqrt{9(-1)(10)}

= \sqrt{9} × \sqrt{-1} × \sqrt{10}

= 3i\sqrt{10}

in the form Ai\sqrt{B}

with A = 3 and B = 10

5 0
2 years ago
Jon ran 4 miles in 35<br> minutes. How long did it<br> take him to run a mile
sesenic [268]

Answer:

35/4 minutes per mile

Step-by-step explanation:

rate = time/distance, therefore the answer is 35/4

4 0
3 years ago
Find b and then solve the equation:(b−5)x2−(b−2)x+b=0, if one of its roots is0.5
grigory [225]

Answer:

b = ⅓

x = ½, -1/7

Step-by-step explanation:

(b−5)x² − (b−2)x + b = 0

(b - 5)(0.5)² - (b - 2)(0.5) + b = 0

0.25b - 1.25 - 0.5b + 1 + b = 0

0.75b = 0.25

b = ⅓

(⅓−5)x² − (⅓−2)x + ⅓ = 0

(-14/3)x² + (5/3)x + 1/3 = 0

14x² - 5x - 1 = 0

14x² - 7x + 2x - 1 = 0

7x(2x - 1) + (2x - 1) = 0

(7x + 1)(2x - 1) = 0

x = 0.5, -1/7

4 0
4 years ago
Read 2 more answers
A man walked steadily from 11 am to 2.30 pm at 5 kilometres per hour how far did he walk!
matrenka [14]

Answer:

Distance traveled 17.5 kilometers

Step-by-step explanation:

We can use the following equation to find the distance traveled,

Distance traveled = Speed * Time

First we need to find the total time he walked = 2.30 p.m. - 11.a.m.

                                                                             =3.5 hours

Now we can substitute the values to the equation,

Distance traveled = 5 kilometers per hour * 3.5 hours

                              = 5*3.5 kilometers

                              = 17.5 kilometers


3 0
3 years ago
Anybody know the correct answer?
earnstyle [38]

Since \csc^2{x}=\frac{1}{\sin^2{x}} and \cot^2{x}=\frac{\cos^2{x}}{\sin^2{x}}, we can rewrite the right side of the equation as

\frac{1}{\sin^2{x}}-\frac{\cos^2{x}}{\sin^2{x}} =\frac{1-\cos^2{x}}{\sin^2{x}}

Using the identity \sin^2{x}+\cos^2{x}=1, we can subtract \cos^2{x} from either side to obtain the identity \sin^2{x}=1-\cos^2{x}

substituting that into our previous expression, the right side of our equation simply becomes

\frac{\sin^2{x}}{\sin^2{x}}=1

We can now write our whole equation as

3\tan^2{x}-2=1

Adding 2 to both sides:

3\tan^2{x}=3

dividing both sides by 3:

\tan^2{x}=1

\tan{x}=\pm1

When 0 ≤ x ≤ π, tan x can only be equal to 1 when sin x = cos x, which happens at x = π/4, and it can only be equal to -1 when -sin x = cos x, which happens at x = 3π/4

4 0
3 years ago
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