Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
Answer:
The answer is "Option A"
Step-by-step explanation:
The Side Angle Side postulates if the two sides, as well as the angle of a triangular, are two sides consistent as well as the angle of a separate triangle included, the two triangles are compatible.
In this situation, the triangle ABC contains two sides AC and BC, with angle C included but which corresponds with both the sides BD and BC, as well as the angle B included in the triangle BCD Added.
2(x +4)-6(q/9)
The slash represents a division sign.
P = 2L + 2W ....subtract 2L from both sides
P - 2L = 2W ...divide both sides by 2
(P - 2L) / 2 = W .....can also be written like (P/2) - L = W
