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3 years ago

Which of the following expressions is a polynomial?

Mathematics

2 answers:

vekshin13 years ago

6 0

See the attached file resolution.

Cloud [144]3 years ago

5 0

Polynomial requirements
1. never divide by a placeholder
2. variable exponent has to be a whole number
3. can't have infinte terms

by 1. we eliinate 2nd one

by 2. we eliminate first one (√x=x^1/2) and 3rd one because it has an exponent in placeholder

thie leaves us with last one
f(x)=2x³-5x⁵-(2/9)x²+9

last one is answer

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Please help easy stuff.....

Karo-lina-s [1.5K]

The answer is 27
Remember that the number inside the lines are always positive so in this case it will be
|-8|+19 which will equal to
8+19=27

7 0

3 years ago

Read 2 more answers

1 ln(1) + 2 ln(2) + 3 ln(3) + ⋯ + 10 ln(10)

Lapatulllka [165]

Answer:

$\ln(1\cdot2^{2} \cdot3^{3}\cdot4^{4} ...\cdot10^{10} )$

Step-by-step explanation:

By logarithm rules

$\ln1+2\ln2+3\ln3+....+10\ln10\\\ln1+\ln2^2+\ln3^3+....\ln10^{10}\\\ln(1\cdot2^{2} \cdot3^{3}\cdot4^{4} ...\cdot10^{10} )$

6 0

3 years ago

it takes approximately 1200 KG of coal to produce the energy needed to make 1 kg of aluminum is a single soda can requires 15 g

Pavel [41]

see so,1200 kg of coal=1kg of aluminum

if 1 soda can needs 15g of aliminium so

1200/15=80kg coal will be needed for 1 can of soda.

4 0

3 years ago

Select the true statement. A. Paul's data has a larger overall spread than Sally's data. B. The interquartile range of Paul's da

Mila [183]

Answer:

I just did the test and got it right the answer is A. Paul's data has a larger overall spread than Sally's data.

Step-by-step explanation:

6 0

3 years ago

Berto invested in a precious mineral. The value of the mineral tend to increase by about 11% per year. He invest $40,000 in 2015

stealth61 [152]

the difference from 40000 to the future value in 2020, namely 5 years later is simply the yield or interest amount.

$\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$40000\\ r=rate\to 11\%\to \frac{11}{100}\dotfill &0.11\\ t=years\dotfill &5 \end{cases} \\\\\\ I=(40000)(0.11)(5)\implies I=22000$

5 0

3 years ago