H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
Answer:
the awnser is b
Step-by-step explanation:
all you have to do is put 45 over 100 to get that percentage
X=12 because 3 times 12 equals 36. if you divide by 3 on both sides you would be left with that
Answer:
B. y= -x^2+50x-300
Step-by-step explanation:
A. y^2=4x^2-100
B. y= -x^2+50x-300
C. x=-y^2-400
D. x^2=-6y^2+200
we are to find profits (y) when the company sells x items
Option A can be used to calculate the profit (y) squared
Option B can be used to calculate profits (y)
Option C can be used to calculate items sold(x)
Option D can be used to calculate items sold squared(x^2)
We are asked to find the weekly profit (y) function which eliminate options A, C and D leaving us with option B
Therefore, the weekly profits (y) function in thousands of dollars when the company sells x items is
B. y= -x^2+50x-300
