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kupik [55]
3 years ago
9

Which expression represents the distance between -3 and 5 on the number line?

Mathematics
2 answers:
marta [7]3 years ago
5 0
The expression that represents the distance between -3 and 5 on the number line is “-3-5”.
kondor19780726 [428]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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What are the solutions of x^2-2x+5=0
Damm [24]

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1 + 2i and 1 – 2i

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The diagonals of square ABCD intersect at point E. If BE = 2x + 1, and AC = 3(6x - 4), find BD.
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Step-by-step explanation:

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What is the commutative and associative propertys?
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5 0
3 years ago
If a=2b^3 and b= -1/2c ^-2,express a in terms of c.
ElenaW [278]

Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

6 0
3 years ago
I. Let f(x) = 2x – 1, g(x) = 3x, and h(x) = x2<br> + 1. Compute the following:<br><br> 1. f(g(-1))
aleksandrvk [35]
F(g(-1))
g(-1) = 3(-1) = -3
f(-3) = 2(-3) -1 = -6 -1 = -7
3 0
3 years ago
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