Explanation:
The problem says that the hairless phenotype never breeds true. That means that it's not the result of a homozygous genotype (H₁H₁ or H₂H₂), so it is caused by the heterozygous genotype (H₁H₂).
The <u>expected </u>offspring from the cross between two Mexican hairless would be:
<h3>P
H₁H₂ x
H₁H₂</h3><h3>F1 1/4
H₁H₁, 2/4
H₁H₂ and 1/4
H₂H₂.</h3>
And the <u>expected</u> phenotypic ratio 3:1. However, the observed offspring shows a 2:1 ratio. What's happening?
If the observed phenotypic ratio in the offspring of a monohybrid cross (a single gene with two alleles) is 2:1, we can suspect that one of the genotypes is lethal in homozygosis and therefore does not appear in the progeny (the puppies are born dead).
If we proposed that the H₂ allele is lethal in homozygosis, then:
- The H₁H₁ genotype would cause normal puppies --> 1
- The H₁H₂ genotype would cause hairless puppies --> 2
- The H₂H₂ is lethal and causes the death of puppies --> 0
The phenotypic ratios change to 2:1, as observed in the experiment.
<span>The types of effects that the surgery had on the rats were documented with their bar-pressing behavior. The differences and changes from the injections effected the rats in certain ways. The location of the injection and which types that was more pleasurable for the rat is something that needs further investigation.</span>
Answer: the half life of the material is four years
Photosynthesis, because the equation is using light energy and producing oxygen, like a plant, which use photosynthesis to make food.
Based on the scenario above, the best intervention that the
nurse should prioritize is to provide the mother instructions in regards of
calling the poison control because the mother should call the poison control in
order to ask the steps that she should start or take when treating ingestion.
