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4 years ago

A square with side length 4 and a rectangle with width 8 and length 8.5, are they similar?

Mathematics

1 answer:

LiRa [457]4 years ago

7 0

Answer:

No, they are not.

If a quadrilateral is similar to a square, then the quadrilateral is a square.

Indeed, in this case all angles of the quadrilateral are right angles and all sides are of the same length.

Step-by-step explanation:

You might be interested in

Rewrite the expression with a rational exponent as a radical expression.

tatiyna

Answer:

First option is correct.

$\sqrt[10]{4}$

Step-by-step explanation:

Given:

The given expression is $(4^{\frac{2}{5}})^{\frac{1}{4}}$

We write the given expression with a rational exponent as a radical expression such as.

$=(4^{\frac{2}{5}})^{\frac{1}{4}}$

Simplify the above equation by multiplication of powers.

$=(4^{\frac{2}{5}\times \frac{1}{4}})$

$=(4^{\frac{1}{5}\times \frac{1}{2}})$

$=(4^{\frac{1}{5\times 2}})$

$=(4^{\frac{1}{10}})$

$=\sqrt[10]{4}$

Therefore, The answer is $=\sqrt[10]{4}$ .

4 0

4 years ago

Just don’t understand the question to get the answer

ivann1987 [24]

Answer:

not sure if u saw the comment but

7 and 8 are congruent, and 8 is congruent to 10

that maybe the rest of the answer

7 0

2 years ago

jana ran the first 3.5 miles of a 5 mile race in 1/3 hour what was the rate in miles per hour for this first part of the race? e

Grace [21]

2.8 1/3 of 3.5 is .7 .7 - 3.5=2.8

4 0

3 years ago

Find the answer for x that makes this number sentence true: 2x + 9 > 11

Nana76 [90]

Answer:

2 x <u>2</u> + 9 > 11

2 x 2 = 4

4 + 9 = 13

13 > 11

Therefore, x = 2.

Step-by-step explanation:

I hope this helps! ^w^

3 0

3 years ago

A real estate company wants to build a parking lot along the side of one of its buildings using 800 feet of fence. If the side a

Elden [556K]

Answer:

80,00 $ft^{2}$

Step-by-step explanation:

According to my research, the formula for the Area of a rectangle is the following,

$A = L*W$

Where

A is the Area
L is the length
W is the width

Since the building wall is acting as one side length of the rectangle. We are left with 1 length and 2 width sides. To maximize the Area of the parking lot we will need to equally divide the 800 ft of fencing between the <u>Length and Width.</u>

800 / 2 = 400ft

So We have 400 ft for the length and 400 ft for the width. Since the width has 2 sides we need to divide 60 by 2.

400/2 = 200 ft

Now we can calculate the maximum Area using the values above.

$A = 400ft*200ft$

$A = 80,000ft^{2}$

So the Maximum area we are able to create with 800 ft of fencing is 80,00 $ft^{2}$

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Read more on Brainly.com - brainly.com/question/12953427#readmore

3 0

3 years ago