Given the following exponential function, identify whether the change

Mathematics

1 answer:

kodGreya [7K]3 years ago

7 0

It shows a change in growth, and has a percentage rate that is positive, I .

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Find sin(x/2), cos (x/2), and tan(x/2) from the given information.

zhannawk [14.2K]

Step-by-step explanation:

sin(x/2) = sqrt((1 - cos(x))/2)

cos(x/2) = sqrt((1 + cos(x))/2)

tan(x/2) = sin(x/2)/cos(x/2)

sin(x) = 15/17

so, we can assume the Hypotenuse of the right-angled triangle is 17, the vertical leg is 15.

via Pythagoras we get the 3rd, horizontal side :

17² = 15² + side²

289 = 225 + side²

64 = side²

side = 8

cos(x) = 8/17

sin(x/2) = sqrt((1 - 8/17)/2) = sqrt(9/34) = 3/sqrt(34) =

= 0.514495755...

cos(x/2) = sqrt((1 + 8/17)/2) = sqrt(25/34) = 5/sqrt(34) =

= 0.857492926...

tan(x/2) = 3/sqrt(34) / 5/sqrt(34) = 3/sqrt(34) × sqrt(34)/5 =

= 3/5 = 0.6

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2 years ago

Question 24

andreyandreev [35.5K]

Answer:

parallel bc they have same gradient

Step-by-step explanation:

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3 years ago

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Archie has a bag of grass seed that he will use to cover a new field. The bag contains information about the area of the ground

gladu [14]

25:1 is the constant of proportionality between the number of square yards of grouse to be covered and the number of scoops of grass seed needed.

This was found by reducing the any of the 4 provided proportions, each would end up leading you to 25/1

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3 years ago

Which function does not have a vertical asymptote? A) y=(x) /(1-x²) . B) y=(5x) /(1-2x²) . C) y=(5x-1) /(3+x^2) . D) (5x) /(x+x²

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A function has a vertical asymptote $x=a$ at point a, where the denominator becomes equal to 0.

A. The denominator of the function $f(x)=\dfrac{x}{1-x^2}$ turns into 0 at $x=1$ or $x=-1.$ Then $x=1$ and $x=-1$ are two vertical asymptotes of this function.

B. The denominator of the function $f(x)=\dfrac{5x}{1-2x^2}$ turns into 0 at $x=\sqrt{\frac{1}{2}}$ or $x=-\sqrt{\frac{1}{2}}$ Then $x=\sqrt{\frac{1}{2}}$ and $x=-\sqrt{\frac{1}{2}}$ are two vertical asymptotes of this function.