Answer:
Rhian did better in the Math test.
Step-by-step explanation:
Given: Rhian scored 
out of 
in a Math test. In the English test she scored 
out of 
.
To find: In which test did she do better?
Solution:
We have,
Rhian scored out of in a Math test.
Rhian scored out of in an English test.
So, first we need to find the percentage of the marks scored.
Percentage in the Math test 
.
Percentage in the English test 
.
Clearly, the percentage in the Math test is greater than the percentage in the English test.
So, Rhian did better in the Math test.
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
Top Right
Step-by-step explanation:
231/pi(3)^2 =8.17
Round down to 8
Answer:
540 degrees in a pentagon
4 + 8 + 6 + 4 + 5 = 27
540/27 = 20
4 X 20 = 80 degrees
8 X 20 = 160 degrees
6 X 20 = 120 degrees
4 X 20 = 80 degrees
5 X 20 = 100 degrees
Answer:
12 x 12 = 144, 12 x 13 = 156
Step-by-step explanation:
