To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D
The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3
Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.
Answer:
x =10
Step-by-step explanation:
Using the pythagoras theorem om one of the right triangle;
(√74)² = (x/2)²+7²
74 = (x/2)²+49
(x/2)² = 74 - 49
(x/2)² = 25
Square root both sides
√ (x/2)² = ±√25
x/2 = ±5
x = 2 * ±5
x = ±10
Hence the value of x is 10
Answer:
a) 16.25 centimeters
b) 6.8 centimeters
Step-by-step explanation:
We can set up a proportion for both of these problems.
a) Look at the longest side of each triangle. We can set up a fraction: 7.2/18. We can also set up a fraction for XZ and PR:
6.5/x
x represents the length you're trying to find.
Since the triangles are similar, we have an equation:
7.2/18=6.5/x
Cross multiply
16.25
XZ is 16.25 centimeters long.
b)
We can do same thing:
7.2/18=x/17
Cross multiply
6.8
QR is 6.8 centimeters long.
Hope this helps!
