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pentagon [3]
4 years ago
5

By 8:00 a.m., the snack bar had made $3,256 in sales. By noon, the snack bar’s total sales were $8,821. On average, how much mon

ey did the snack bar take in each hour between 8:00 a.m. and noon?
$814.00
$1,391.25
$2,205.25
$5,565.00
Mathematics
2 answers:
Margaret [11]4 years ago
6 0

Answer:

$1391.25 per hour

Step-by-step explanation:

melisa1 [442]4 years ago
5 0

Step-by-step explanation: The answer is $1,391.25

$8,821 - $3,256 = $5,565

12hr - 8hr = 4hr

$5,565/4hr

$1,391.25 an hr

im in 8th grade :))

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navik [9.2K]

Answer:

The best recommendation is to: Increase the sample size.

Step-by-step explanation:

The width of a confidence interval  W=2\times CV\times \frac{SD}{\sqrt{n}} ,depends on three things,

  1. Sample size (n)
  2. Standard deviation
  3. Confidence level

To decrease the width the following options can be used:

  • Increase the sample size.

Since the sample is inversely proportional to the width of the confidence interval, increasing the value of <em>n</em> will decrease the width.

  • Decrease the standard deviation.

The standard deviation is directly proportional to the width of the confidence interval. On decreasing the standard deviation value the width of the interval will also decrease.

  • Decrease the confidence level.

The critical value of the distribution is based on the confidence level. Higher the confidence level, higher will be critical value.

So, on deceasing the confidence level the critical value will decrease, hence decreasing the width of the interval.

Thus, the best recommendation is to: Increase the sample size.

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3 years ago
Find the measure of an exterior angle of a regular polygon with 9 sides
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Answer: 40°

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3 0
3 years ago
3/m = 45/50 HELP, WILL GIVE BRAINLIST IF PERFECT ANSWER, its hard
Lana71 [14]

Answer:

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49. From 3 coin tosses, there are 8 possible outcomes:

... TTT, TTH, THT, THH, HTT, HTH, HHT, HHH

All but the first have at least one head, so 7/8 of the possibilities have at least one head. That's 87.5% (not among your choices).

Likewise, all but the last listed outcome have at least one tail. The problem is symmetrical that way when the coin is fair. 87.5% of outcomes have at least one tail.

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Perhaps you can tell I read your question as having two parts. If your question is the probability of getting at least one head AND at least one tail, you can see that condition includes 6 of the 8 outcomes, or 75%, matching selection d.

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3 years ago
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