Answer:
7.5^2
56.25
Step-by-step explanation:
Answer:
p = -4, q = -3
Step-by-step explanation:
y = -2x +4 ... (1) perpendicular bisector of AB, slope = -2
slope of AB = 1/2
Line AB pass (8,3): (y-3) / (x-8) = 1/2
AB equation: y-3 = 1/2(x-8) y = 1/2x - 1 ... (2)
(2)-(1): 5/2 x = 5 x = 2
y = 0 (2,0) intercept of bisector and AB, it is midpoint of A (8,3) and (p,q)
(8+p)/2 = 2
<u>p = -4</u>
(3+q)/2 = 0
<u>q = -3</u>
Given:
There are given that the cos function:

Explanation:
To find the value, first, we need to use the half-angle formula:
So,
From the half-angle formula:

Then,
Since 105 degrees is the 2nd quadrant so cosine is negative
Then,
By the formula:

Then,
Put the value of cos210 degrees into the above function:
So,

Final answer:
Hence, the value of the cos(105) is shown below:
Answer:
True
Step-by-step explanation:
an obtuse triangle is a big one, an acute triangle is a small one. They are both triangles, but they are not similar besides that