All categories

3 years ago

Help ASAP pls :) brainly to whoever has the right answer first :D

Mathematics

1 answer:

Fed [463]3 years ago

6 0

Answer:

0.02 (rational)

2 (rational)

Square root of 2 (irrational)

Square root 1/2 (irrational)

Step-by-step explanation:

Rational numbers are numbers that can be in form of a/b such that a and b are not zeros. In other words, a and b are integers ranging from 1 to infinity.

Conversely, irrational numbers are numbers that are endless and are non repeating digits after decimal point.

Thus, from the questions above;

$0.02 = \frac{2}{100} = rational \: number$

$2 = \frac{2}{1} = rational \: number$

$\sqrt{2} = 1.41421356 = irrational \: number$

$\sqrt{ \frac{1}{2} } = 0.70710678 = irrational \: number$

You might be interested in

To convert a distance of 2200 yards to miles, which ratio could you multiply by? Remember that 1 mile=1760yards

Mnenie [13.5K]

Multiply both sides by 2200/1760 * 2200/1760 and you get 1.25

6 0

2 years ago

Read 2 more answers

Need help with geometry question?

Nuetrik [128]

Answer: A, Corresponding; Vertical

Step-by-step explanation: The answer for angles 1 and 5 are Corresponding Angles (Elevator Angles) and angles 1 and 4 are Vertical Angles.

All Angles besides a Linear Pair and Same-Side Interior Angle are Congruent.

5 0

3 years ago

What's the input lol *photo attatched*

marishachu [46]

-20+1= -19
-19/2= -9.5

Check:
-9.5x2= -19
-19-1= -20

3 0

2 years ago

Assume that we want to construct a confidence interval. Do one of the following, as appropriate:_________.

andreyandreev [35.5K]

Answer:

B. z Subscript alpha divided by 2 zα/2 = 1.96.

Step-by-step explanation:

We are given that we want to construct a confidence interval. For this, the summary statistics for randomly selected weights of newborn girls:

n = 236, $\bar x$ = 30.3 hg, s = 7.2 hg. The confidence level is 95%.

As we can clearly see here that the population standard deviation is unknown and the sample size is also very large.

It has been stated that when the population standard deviation is unknown, we should use t-distribution but since the sample size is very large so we can use z distribution also as it is stated that at very large samples; the t-distribution corresponds to the z-distribution.

Here, $\alpha$ = level of significance = 1 - 0.95 = 0.05 or 5%

$\frac{\alpha}{2}=\frac{0.05}{2}$ = 0.025 or 2.5%

So, the value of $Z_(_\frac{\alpha}{2} _)$ in the z table is given as 1.96 with a 2.5% level of significance.

3 0

3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

8 0

3 years ago